Pass Guaranteed Quiz Salesforce - JS-Dev-101 - Professional Exam Salesforce Certified JavaScript Developer - Multiple Choice Actual Tests
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Salesforce JS-Dev-101 Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Objects, Functions, and Classes | 25% | - ES6 classes, inheritance, modules, decorators - Function types, scope, closures, arrow functions - Object creation, properties, prototypes |
| Topic 2: Variables, Types, and Collections | 23% | - Data types, type coercion, truthy/falsy values - JSON parsing and manipulation - Strings, numbers, dates, arrays and methods - Variable declaration and scope |
| Topic 3: Testing | 7% | - Unit test structure and effectiveness - Test coverage and improvement |
| Topic 4: Asynchronous Programming | 13% | - Callbacks, promises, async/await - Event loop and execution flow |
| Topic 5: Debugging and Error Handling | 7% | - Error types and handling strategies - Console usage, breakpoints and debugging techniques |
| Topic 6: Server Side JavaScript | 8% | - Package management and CLI tools - Node.js fundamentals and core modules |
| Topic 7: Browser and Events | 17% | - Browser APIs and developer tools - Event handling, propagation, listeners - DOM selection and manipulation |
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q37-Q42):
NEW QUESTION # 37
Refer to the code
below:
```html
<html>
<body>
<div id="logo">Hello
Logo!</div>
<button id="test">Click
me</button>
</body>
<script>
function printMessage()
{
console.log('This is a test message');
}
let el =
document.getElementById('test');
el.addEventListener("click", printMessage,
false);
</script>
</html>
- A. Add event. removetventiistener(); tO printlessage function
- B. Add event. stopPropagation(); 10 printivessage function
- C. Add event.stoppropagation(); to winontdoado evewnt handier
- D. Add event. removefventListener(); 10 window. onLoad event handier
Answer: B
NEW QUESTION # 38
Refer to the code:
Given
the code above, which three properties are set pet1? Choose 3 answers:
- A. canTalk
- B. Owner
- C. Name
- D. Size
- E. Type
Answer: A,D,E
NEW QUESTION # 39
Refer to the following code
(correcting the missing template literal backticks):
let codeName =
'Bond';
let sampleText = `The name is ${codeName}, Jim ${codeName}`;
A
developer is trying to determine if a certain substring is part of a
string.
Which three code statements return true?
- A. sampleText.includes('The', 1);
- B. sampleText.includes('Jim');
- C. sampleText.indexOf('Bond') !== -1;
- D. sampleText.substring('Jim');
- E. sampleText.includes('Jim', 4);
Answer: B,C,E
Explanation:
Comprehensive and Detailed Explanation From Exact Extract
JavaScript knowledge:
First, compute sampleText:
let codeName =
'Bond';
let sampleText = `The name is ${codeName}, Jim ${codeName}`;
The
template literal evaluates to:
"The name is Bond, Jim Bond"
Now evaluate
each statement:
Option A:
sampleText.includes('Jim');
String.prototype.includes(substring) returns true
if substring occurs anywhere in the string.
sampleText clearly contains "Jim"
("The name is Bond, Jim Bond").
So this returns true.
Option B:
sampleText.includes('The', 1);
includes(searchString, position) starts
searching from the given position index.
"The name is Bond, Jim Bond" has
"The" starting at index 0.
Starting search at index 1 means "The" at index 0
is not considered, and there is no second "The".
So this returns
false.
Option C: sampleText.includes('Jim', 4);
"Jim" appears after "The
name is Bond, " which is longer than 4 characters; the index of "Jim" is well
past 4.
So when searching from index 4, "Jim" is still found.
This returns
true.
Option D: sampleText.indexOf('Bond') !==
-1;
String.prototype.indexOf(substring) returns:
-1 if the substring is
not found,
Otherwise, the starting index of the first occurrence.
"Bond"
appears twice in "The name is Bond, Jim Bond".
So sampleText.indexOf('Bond')
is some non-negative index (for the first occurrence).
Therefore
indexOf('Bond') !== -1 is true.
Option E:
sampleText.substring('Jim');
substring expects numeric indexes:
substring(startIndex, endIndex?).
If given a string "Jim" as the argument,
JavaScript coerces it to a number:
Number('Jim') → NaN
NaN for startIndex
is treated as 0.
So sampleText.substring('Jim') is effectively
sampleText.substring(0), which returns the full string "The name is Bond, Jim
Bond".
This is a string, not a boolean. The question asks "which code
statements return true?" This statement returns a string, not the boolean value
true.
Thus, the three statements that actually return true (boolean)
are:
Study Guide / Concept Reference (no links):
Template literals and ${}
interpolation
String.prototype.includes(searchString,
position?)
String.prototype.indexOf(substring) and checking for !==
-1
String.prototype.substring(start, end?) and argument coercion
Boolean
vs non-boolean return types in string
methods
________________________________________
NEW QUESTION # 40
A page loads 50+ <div
class="ad-library-item"> elements, all ads.
Developer wants to quickly and
temporarily remove them.
Options:
- A. Use the DOM inspector to remove all elements containing the class ad-library-item.
- B. Use the browser console to execute a script that removes all elements containing the class ad-library-item.
- C. Use the DOM inspector to prevent the load event from firing.
- D. Use the browser console to execute a script that prevents the load event from firing.
Answer: B
Explanation:
________________________________________
Comprehensive and
Detailed Explanation From Exact Extract JavaScript Knowledge The
goal:
"Temporarily and quickly remove them."
The fastest way is to run a
script in the browser console that removes all such
elements:
document.querySelectorAll('.ad-library-item').forEach(el =>
el.remove()); This immediately removes all 50+ elements and requires no page
reload.
Option analysis:
A & B: Preventing load events is unreliable
and does not remove already-created DOM nodes.
C: Correct-console code can
remove all matching DOM elements instantly.
D: Possible but extremely slow;
removing 50+ elements one by one in the inspector is not "quick." Therefore, C
is the best answer.
________________________________________
JavaScript
Knowledge Reference (text-only)
The browser console can run arbitrary
JavaScript that manipulates the DOM.
document.querySelectorAll() returns all
matching DOM nodes.
Nodes can be removed using .remove().
NEW QUESTION # 41
developer removes the HTML class
attribute from the checkout button, so now it is
simply:
<button>Checkout</button>.
There is a test to verify
the existence of the checkout button, however it looks fora button with class=
"blue". The test fails because no such button is found.
Which type of test
category describes this test?
- A. True negative
- B. True positive
- C. False negative
- D. False positive
Answer: C
NEW QUESTION # 42
......
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